Question

The energy of electron in the first Bohr orbit of H atom is -13.6 eV the possible energy value of the excited state of electrons in Bohr orbits of hydrogen is

Answer 1

Energy of an electrons = -(2.18x 10-18)/n2

Where n= principal quantum number

Now the Energy associated with the fifth orbit of hydrogen atom is

\begin{align}E_{5}=\frac{-(2.18\times10^{-18})}{(5)^{2}}=\frac{-2.18\times10^{-18}}{25}\end{align}

                                E5 = –8.72 × 10–20 J

 

(ii) Radius of Bohr’s nth orbit for hydrogen atom is given by,

rn = (0.0529 nm) n2

For,

n = 5

r5 = (0.0529 nm) (5)2

r5 = 1.3225 nm