Question

The energy of electron in the first orbit of Helium is
- 871.6 x 10-20 J. The energy of the electron in
the first orbit of hydrogen atom would be​

Answer 1

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Answer 2

Answer:

2.176*10^-18 J.

Explanation:

From the question we get that the energy of the electron in the first orbit of Helium is given as - 871.6 x 10-20 J.

While we know that the energy of the electron in the first orbit of hydrogen atom is given by the equation En=Eo*Z^2/n^2.

Where, atomic number of hydrogen is given as z=1 and the number of orbit is given as n=1. So, substituting the values in the equation we will get En=13.6*1^2/1^2 which on solving we will get 13.6 eV. So, 13.6*1.6*10^-19 J will be 2.176*10^-18 J.