Question

the energy of electron with de broglie wavelength of 10^-10 meter in ev is​

Answer 1

Answer:

Explanation:

E= 10 eV = 10X1.6X10^-19 Joules  ( Given)

Mass of the electron m= 9.1X10^-31 kg

The de Broglie wavelength is described as -

Λ = h/(2mE)^1/2

Where, h is Planck’s constant , m is the mass of electron  and E is the energy of the electron

Therefore,

Λ = 6.626 × 10−34/(2 × 9.1 × 10−31 × 10 × 1.6 × 10−19)1/2

= 0.499 × 10^-9m

= 0.499nm

Thus, the energy of electron with de broglie wavelength of 10^-10 meter in ev is​ 0.499nm

Answer 2

Answer:

E= 10 eV = 10X1.6X10^-19 Joules ( Given)

Mass of the electron m= 9.1X10^-31 kg

The de Broglie wavelength is described as -

Λ = h/(2mE)^1/2

Where, h is Planck’s constant

, m is the mass of electron and E is the energy of the electron

Therefore,

Λ = 6.626 × 10−34/(2 × 9.1 × 10−31 × 10 × 1.6 × 10−19)1/2

= 0.499 × 10^-9m

= 0.499nm

Thus, the energy of electron with de broglie wavelength of 10^-10 meter in ev is​ 0.499nm

Explanation: