the energy of emitted photoelectron depends upon
Answers
Metals which do not become superconducting usually exhibit resistivity proportional to T2 close to zero temperature (due to electron-electron scattering which dominates over electron-phonon scattering at low enough temperature; see: Fermi liquid theory). Extrapolating to zero temperature yields a finite intercept whose value is determined by impurity scattering--how dirty the material is. Thus, a perfect metal with no impurities and no defects will be a perfect conductor at zero temperature (which is a distinct animal from a superconductor), but such an object doesn't exist in the real world.
Explanation:
Maximum kinetic energy of the photoelectrons emitted K.E_{max} = hv-∅
where ϕ is the work function of the metal, ν is the frequency of the incident photon.
Wavelength of the incident photon lamda=v/c
Thus kinetic energy of the emitted photoelectrons depends on wavelength, frequency of the incident photon and work function of the metal but does not depend on the intensity.