Question

The energy of emitted photoelectrons
from a metal is 0.9 eV. The work function
of the metal is 2.2 eV. Then the energy
of the incident photon is​

Answer 1

Answer:

Explanation:

Total energy of incident photon=Kinetic energy of electron+work function.

hv=K.E.+hv·      

hv=0.9+2.2

hv=3.1eV

Energy of the incident photon is 3.1electron vault

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