Question

The energy of the election in second Bohis orbits
the Hydrogeo atom is 3.4ev then what is the energy of electron in second bohrs orbit of he+ion

​

Answer 1

Answer:

K.E.=

2

1

mv

2

....(1)

mvr=

2π

nh

→ (Bohr's model)

(mv)

2

=

4π

2

r

2

n

2

h

2

mv

2

=

m

1

×

4π

2

r

2

n

2

h

2

....(2)

Put (2) in (1)

K.E⇒

2

1

×

m

1

×

4π

2

r

2

n

2

h

2

Now, n

o

=2,r

1

=a

o

,r

2

=a

o

×(2)

2

=4a

0

.

K.E.⇒

2

1

×

4π

2

(4a

o

)

2

m

2

2

h

2

⇒

32π

2

a

o

2

m

h

2