The energy of the electron in an orbit of hydrogen atom is given by En = - 1311.8 / n2 KJ/mol. The energy of electron in the first excited state of H – atom is
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12th
Physics
Atoms
Bohr's Model
The energy of the electron ...
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Asked on December 27, 2019 by
Shristi Nirmala
The energy of the electron of hydrogen atom in its nth orbit is given by E
n
=−
n
2
13.6
electron volt(eV). Based on this formula.
(i) Draw different energy levels corresponding to n=1,2,3,4,5,6 and ∞.
(ii) Show Lyman and Baler series of emission spectrum of hydrogen atom by drawing various electronic transitions.
(iii) Find the ionisation energy of hydrogen atom.
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ANSWER
Energy of electron in nth orbit of Hydrogen atom is given by E
n
=
n
2
−13.6
So energy of electron in n=1 to n=6 is calculated as shown in the above figure.
E
1
=
1
2
−13.6
=−13.6 eV
E
2
=
2
2
−13.6
=−3.4 eV
and so on.
Lyman series is obtained in the hydrogen atom when an electronic transition takes place from n
2
=2,3,4,5,6,... to n
1
=1. Whereas, Balmer series is obtained in the hydrogen atom when an electronic transition takes place from n
2
=3,4,5,6,... to n
1
=2. These transition is also shown in the above diagram.
(iii)
Ionisation energy of hydrogen atom E
ionisation
=E
∞
−E
1
⟹ E
ionisation
=0−(−13.6)=13.6 eV