Question

The energy of the electron in Bohr's first orbits is
The energy of the electron in its first
excited state is :
a) -3.4 eV
b) -278 ev
c) -6.8 ev
d) -102 ev
​

Answer 1

Answer:

a) -3.4 eV

Explanation:

We know that

$E = -13.6\frac{z^{2} }{n^{2} }$

assuming z=1 (Hydrogen Atom)

E=$\frac{-13.6}{2^{2} }$

E=-3.4