Question

the energy of the lowest state in a one dimensional potential box of length a is​

Answer 1

Answer:

The lowest possible energy for a particle is NOT zero (even at 0 K). This means the particle always has some kinetic energy. The square of the wavefunction is related to the probability of finding the particle in a specific position for a given energylevel

Answer 2

Answer:

The energy of the lowest state in one dimensional potential box of length a is   $E_{1} = \frac{h^{2} }{8ma^{2} }$

Explanation:

Energy in one dimensional potential box is given by equation           $E {n}=\frac{n^{2}h^{2} }{8ma^{2} }$   -----------(i)

where ,     n =energy level              

             h= Planck's constant              

            a= length of potential box              

            m= mass of particle

lowest energy  state is ground state which is at n= 1

so energy becomes :(n=1)        

   $E{1} = \frac{h^{2} }{8ma^{2} }$

Hence lowest energy level is   $E_{1} = \frac{h^{2} }{8ma^{2} }$ .