the energy possessed by the neon atom at 27 degree C is
Answers
Answered by
39
Energy = 3/2 KT
= 3/2 × 1.38 × 10^-23 × 300
= 6.21 × 10^-21 J
= 6.21 × 10^-21 × 6.24 × 10^18 eV
= 0.038 eV
Answered by
3
Answer:
hope you understand
Explanation:
thank you
Attachments:
Similar questions