Question

The energy ratio of a photon of wavelength 3000Å and 6000Å
is :
(a) 1 : 1 (b) 2 : 1 (c) 1 : 2 (d) 1 : 4

Answer 1

The energy ratio of photon if wavelength 3000A° and 6000A° is

1) we know equation of energy is given by

E= hc÷Lambda

2) So E1 / E2 = hc ÷lambda 1 × hc÷lambda 2

E1 / E2 = lambda2 ÷ lambda 1

E1 / E2 = 6000A° / 3000A°

E1 / E2 = 2:1

3) So option (b) is the right answer

Answer 2

•The energy ratio of photon of wavelength 3000A° and 6000A° is:-

E= hc /lembda

•Therefore -

E1÷E2= hc/lembda1 ÷ hc/lembda2

•E1÷E2=lembda2÷lemda1

•E1÷E2=6000÷3000

•E1÷E2=2/1

Option (b) is correct.