The energy ratio of a photon of wavelength 3000Å and 6000Å
is :
(a) 1 : 1 (b) 2 : 1 (c) 1 : 2 (d) 1 : 4
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2
The energy ratio of photon if wavelength 3000A° and 6000A° is
1) we know equation of energy is given by
E= hc÷Lambda
2) So E1 / E2 = hc ÷lambda 1 × hc÷lambda 2
E1 / E2 = lambda2 ÷ lambda 1
E1 / E2 = 6000A° / 3000A°
E1 / E2 = 2:1
3) So option (b) is the right answer
Answered by
2
•The energy ratio of photon of wavelength 3000A° and 6000A° is:-
E= hc /lembda
•Therefore -
E1÷E2= hc/lembda1 ÷ hc/lembda2
•E1÷E2=lembda2÷lemda1
•E1÷E2=6000÷3000
•E1÷E2=2/1
Option (b) is correct.
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