Question

The energy released by the fission of one uranium atom is 200 mev. The number of fissions per second required to produce 6.4w power is

Answer 1

troposphere stratosphere mesosphere thermosphere

Answer 2

The number of fissions per second required to produce 6.4 W power if the energy released by the fission of one uranium atom is 200 MeV is 2 × 10^11

- Let the number of fissions per second required to produce a power of 6.4 W be n

- then,

n×200×10^6×1.6×10^-19=6.4

∴ n = 6.4 / ( 200×10^6×1.6×10^-19)

n = 2×10^11