Question

The energy released per fission of a ₉₂U²³⁵ nucleus is nearly
(a) 200 eV (b) 20 eV
(c) 200 MeV (d) 2000 eV

Answer 1

The energy released per fission of a ₉₂U²³⁵ nuclei is nearly 200 MeV.

How much energy is released by nuclear fission?

• The equation given below represents the fission process in the nuclei of Uranium.
• ₉₂U²³⁵ + 0 n 1 →  56 Ba 144 + 36 Kr89 + 3o n1
• Mass of the Uranium = 234.39 + 1.01 = 235.4 amu
• Mass of products = 143.28 + 88.89 +3(1.01) = 235.2 amu
• Now calculate te amount of energy released.
• Energy released = mass difference =235.4−235.2=0.2amu=0.2×931
• Energy released = 200 MeV

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So, the correct answer is (C): 200 MeV

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