Question

The energy required for the ionisation of a certain atom is 3.44×10−18J. The absorption of a photon of unknown wavelength ionises the atom and ejects an electron with velocity 1.03×106 m/sec. Calculate the wavelength of the incident radiation.

Answer 1

HEY.............

This is a case of photoelectric effect, work function being the ionization energy.

∴ Total Energy = KE + work function

hcλ=12mv²+w

(6.626×10⁻³⁴×3×10⁸)/λ=12×9.1×10⁻³¹×(1.03×106)2+3.44×10⁻¹⁸

(2×10⁻²⁵)/λ=3.92×10⁻¹⁸

λ=(2×10⁻²⁵)/(3.92×10⁻¹⁸)

=50.71nm

HOPE ITS HELPFUL

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