The energy required to convert all atoms present in 1.2g magnesium
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Answer:
Given that-----
IE∨1= 120 k j/mole
IE2=240 K J/mole
TOTAL=120+240
=360 K J/mole
24 g of mg =360 K J
1.2 g of mg=1.2×360/24
=18 K J
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Answer is up ......... 18 K j
the energy required to convert all atoms present in 1.2g of magnesium will be 18 K J
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