Question

the energy required to melt one gram of ice is 333J find the no of quanta of infrared radiations of frequency 4.67×10¹³ s that must of absorb in order to melt 2 grams of ice​

Answer 1

Answer:

Energy required to melt 1g ice =33J.

Energy required to melt 10g ice =33×10=330J.

Radiation frequency (ν)=4.67×10

13

s

−1

As we know, the energy of radiation is given by:

E=hν

Here, h= Planck's constant =6.62×10

−34

J.s

∴E=6.62×10

−34

×4.67×10

13

⇒E=3.09×10

−20

J

∴ No. of quanta required =

3.09×10

−20

330

=1.067×10

22

I hope you will understand it!!

Answer 2

Answer:

$n$ ≈ $21 * 10^{21}$

Explanation:

Energy required to melt 1 gm of ice = 333 J

Frequency of IR radiations given to melt ice = $4.67 * 10^{13}$ s

Energy required to melt 2 gm of ice = 666 J

Total energy = $n * hv$

= $n* 6.62*10^{-34} * 4.67 * 10^{13}$

666 = $n * 30.9154 * 10^{-21}$

$n = \frac{666}{31 * 10^{-21} }$

$n$ ≈ $21 * 10^{21}$