the energy required to remove an electron from a metal x is 3.31 × 10^-20 j wavelength of light that can photoeject an electron from metal x is
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Answered by
41
We will use the following equation :
eV = hf
Where eV = Ionisation energy
h = planks constant = 6.62 × 10⁻³⁴
f = frequency of light.
f = C / Y
Where C = speed of light = 3.0 × 10⁸ n/ s
Y = Wavelength
Substituting in the equation :
3.31 × 10⁻²⁰ = (6.62 × 10 ⁻³⁴ × 3 × 10⁸ ) / Y
Y = (1.986 × 10⁻²⁵) / (3.31 × 10⁻²⁰) = 6 × 10⁻⁶ M
Answer :
6 × 10⁻⁶ M
eV = hf
Where eV = Ionisation energy
h = planks constant = 6.62 × 10⁻³⁴
f = frequency of light.
f = C / Y
Where C = speed of light = 3.0 × 10⁸ n/ s
Y = Wavelength
Substituting in the equation :
3.31 × 10⁻²⁰ = (6.62 × 10 ⁻³⁴ × 3 × 10⁸ ) / Y
Y = (1.986 × 10⁻²⁵) / (3.31 × 10⁻²⁰) = 6 × 10⁻⁶ M
Answer :
6 × 10⁻⁶ M
Answered by
33
Answer:
Explanation:
E=3.31×10^-20J
E=he over lambda.
Below is the whole process
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