The energy required to take a satellite to a height ‘h’ above Earth surface (radius of Earth = 6.4 × 10³ km) is E₁ and kinetic energy required for the satellite to be in a circular orbit at this height is E₂. The value of h for which E₁ and E₂ are equal is
(A) 1.6 × 10³ km (B) 3.2 × 10³ km
(C) 6.4 × 10³ km (D) 1.28 × 10⁴ km
Answers
Answered by
6
Answer:
3.2×10*3
f=mac=mv*2/Re+h
Attachments:
Similar questions