Question

the energy stored in a 50 mH inductor carrying a current of 4 A will be

Answer 1

The energy stored in an inductor is given by formula :

E = $\frac{1}{2}$ L I²

where,

L = Inductance of inductor in units of Henry

I = Current in units of Ampere

Given :

L = 50 mH

L = 0.05 H

( 1 millihenry [mH] = 0.001 henry [H] )

I = 4 A

Putting the value of L and I in the formula for Energy :

E =  $\frac{1}{2}$ L I²

E = $\frac{1}{2}$ * 0.05 * 4 * 4

E = $\frac{1}{2}$ * 0.8

E = 0.4 J

Hence,

The energy stored in a 50 mH inductor carrying a current of 4 A will be 0.4 Joules