Question

The energy stored in a capacitor of capacitance 100uF 50J.Its potential difference is?

Answer 1

Answer:

I dont no but same qwestion in my book

Answer 2

Answer:

The energy is stored in a capacitor of capacitance 100uF 50J.Its potential difference is $1\ kV$

Explanation:

• If  C is the capacitance and V is the potential difference between the capacitor plates. Then, Electric potential energy (E) stored in the capacitor  can be expressed as,

            $E=\frac{1}{2} C V^{2}$    ...(1)

Rearrange equation(1) for obtaining an expression for V.

$V^{2} = \frac{2E}{C}$

Or,

$V = \sqrt{\frac{2E}{C} }$        ...(2)

In the question, it is given that,

$E= 50\ J$

$C = 100\ \mu F = 100\times10^{-6}$F

Substitute these  values into equation (2)

$V = \sqrt{\frac{2\times50 }{100\times10^-6} } = 1000\ v = 1\ kV$