Question

the energy stored in a parallel plate capacitor is 24J. what is the potential difference between the plate if the capacitance of the capacitors 3uF?
A. 4kv
B. 16kv
C. 54kv
D. 8kv​

Answer 1

Given:

Energy stored in a parallel plate capacitor is 24 J. The capacitance is 3 uF.

To find:

Potential Difference across capacitor?

Calculation:

The expression relating the energy stored in a capacitor with respect to potential difference and capacitance is :

$E = \dfrac{1}{2} C{V}^{2}$

$\implies 24 = \dfrac{1}{2} (3 \times {10}^{ - 6}) {V}^{2}$

$\implies {V}^{2} = 16 \times {10}^{6}$

$\implies V = \sqrt{ 16 \times {10}^{6} }$

$\implies V = 4 \times {10}^{3} \: volts$

$\implies V = 4 \: kilovolts$

So, the potential difference is 4 kV.

Answer 2

Answer:A

Explanation: