Question

the energy stored in an inductance is 1 joule when a current 0.1 A is established in it .find the self inductance of the coil​

Answer 1

Answer:

The energy stored in a inductor is given by the formula

U=

2

1

Li

2

Given, U=0.1J, I=0.2A

0.1=

2

1

L×(0.2)

2

⇒L=

(0.2)

2

2×0.1

=

0.2×0.2

0.2

L=

2

10

=5 H.

Answer 2

The self-inductance of the coil is 200 Henry.

Given:

The energy stored in inductance is 1 joule when a current is 0.1 A.

To Find:

The self-inductance of the coil​

Solution:

Energy = 1 Joule and Current = 0.1 A

Self-induction is the Induction of an electromotive force in a circuit by a varying current in the same circuit.

Formula,

The energy stored in an inductor = Li²/2

⇒ 1 = L*0.1² / 2

⇒ L = 2 / 0.1²

⇒ L = 200

Therefore the self-inductance of the coil is 200 Henry.

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