Question

the energy stored in magnetic field of solenoid 30 cm long and 3cm diameter wound with 100 turns carrying a current of 10A ?

Answer 1

Answer:

Since we know that,

L = N2 × ρ

given

N = 1000 turns diameter

= 3 cm, L = 30 cm.

ρ = µ0A

= 4π × 10–7 × π × (1.5 × 10 - 2)2

L 0.3

= 29.6088 × 10–10

L = 29.6088 × 10–10 × (103)2

= 29.6088 × 10–4 H

where,

L = length of solenoid

W = 1/2 LI2

= 1/2 × 29.6088 × 10–4 × (10)2

= 0.148 ≈ 0.15 J.

Explanation:

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