Question

The energy supplied by an external agent to charge
a parallel plate capacitor of plate separation d and
plate area of cross-section A such that the uniform
electric field between the plates is E, is
(1) 2062
(1)
Ad
(2) GEO E? Ad
(3) FO E? Ad
(4) FOE
Ad​

Answer 1

Answer:

Explanation:

Since, the question is given to find the electric field between the cells hence we can use the formulae of electric field(E)=C(capacitence)*potential difference (V^2).

So, we know that potential difference across plate V = E.d(d is the distance between the plates).

Capacitence (C) is (AEo/d), let area of the plates be A. Thus combining all we get Electric field as :-

E= (AEo/d)* (E.d)^2.

E = E^2* A * d * Eo.

Answer 2

Answer:

NJ politics and add it to you