Question

The energy used by the iron for 1 minute is 33 kJ, at a voltage of 220 volts. What is the
total power used in kilowatt? In Horsepower?

Answer 1

Given : The energy used by the iron for 1 minute is 33 kJ, at a voltage of 220 volts.

To Find : What is the total power used in kilowatt? In Horsepower?

Solution

Energy = Power * Time

The energy used by the iron for 1 minute is 33 kJ,

33 kJ = 33000 joules

1 minute = 60 secs

1 Joule = 1 Watt. sec

Hence  Power * 60  = 33000

=> Power = 33000/60

=> Power = 550W

Power in kW = 550/1000  = 0.55 kW

1 horse power = 746 watt

Hence in horse power = 550/746  =    0.737 hP

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Answer 2

Given:

The energy used by the iron for 1 minute is 33 kJ, at a voltage of 220 volts.

To find:

The power in :

• kilowatt unit ?

• Horsepower unit ?

Calculation:

Power is defined as the rate of doing work with respect to time.

$\rm \therefore \: P = \dfrac{work}{time}$

$\rm \implies \: P = \dfrac{33 \:kJ }{1 \: min}$

$\rm \implies \: P = \dfrac{33000 \:J }{60 \: sec}$

$\rm \implies \: P = 550 \: watt$

$\rm \implies \: P = \dfrac{550}{1000} \: kilowatt$

$\boxed{ \rm \implies \: P = 0.55 \: kilowatt}$

__________________________

$\rm1 \: HP = 746 \: watt$

$\rm \implies \: 550 \: watt = \dfrac{1}{746} \times 550$

$\boxed{ \rm \implies \: 550 \: watt = 0.737 \: HP }$

Hope It Helps.