Question

The engine have torque 0.17 kNm developed the power 65 kw. What is the rpm of
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Answer 1

Answer:

3778

is the correct answer

Answer 2

Given,

The torque of the engine = 0.17kNm

The power of the engine, P = 65kw

To Find,

The rpm of the engine =?

Solution,

We know that from the formula of power,

Power = Torque * Angular velocity

Angular velocity(ω) = Power(P) / Torque(τ)

ω =  65 kw / 0.17 kNm = $382.35$ $s^{-1}$

We know from the formula of angular velocity,

ω = $2 * \pi * rpm / 60$

rpm = $382.35 * 60 / 2\pi$

rpm = $(382.35 * 60) / (2 * 3.14)$

rpm = 3653 rev./min

Hence, the rpm of the engine is 3653 rev./min.