Question

the engine have torque 0.17 Knm developed the power 65KW. What is the rpm of the engine​

Answer 1

Explanation:

Let "me" be the number x. It is unknown as this point.

81 divided by x = x

81/x = x

81 = x*x ... Multiply both sides by x.

81 = x^2

x^2 = 81

x = sqrt(81)

x = 9

Notice how 54/x = 54/9 = 6. So that checks out.

Answer 2

Answer:

The rpm ( revolution per minute ) of the engine measured is $3653$ rev./min.

Explanation:

Given,

The torque of the engine, $\tau$ = $0.17kN-m$ = $170N-m$

The power of the engine, P =$65kW$ = $65000W$

The engine's rpm ( revolution per minute ) =?

As we know,

• Power = $\tau \times \omega$
• Angular velocity, ω = $\frac{Power}{Torque}$

After putting the given values in the equation, we get:

• Angular velocity, ω = $\frac{65000}{170}$ = $382.35 s^{-1}$

Also,

• Angular velocity, ω = $\frac{2\pi\times rpm}{60}$

Thus,

• rpm = $\frac{\omega \times 60}{2\pi }$
• rpm = $\frac{382.35\times 60}{2\times 3.14}$
• rpm =$3653$ rev./min.

Hence, the engine's rpm ( revolution per minute ) = $3653$ rev./min.