the engine of 0.2kg model air plane exerts a forward force of 10N on the plane while the air exerts a resistive force of 7.5N on the plane. What is the acceleration of the plane along its direction of motion?
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Answer:
forward force=10N
resistive force=7.5N
engine weight=0.2kg
Net Force=forward force-resistive force
= 10-7.5
Net Force= 2.5N
Now,
Net Force=MA
2.5 = 0.2 × A
A= 2.5/0.2
A=12.5 m/s^2
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