The engine of a car produces an acceleration of 6m/s square in the car. if the car pulls a block of the same mass then the acceleration woul?
Answers
Answered by
55
ANSWER
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whatever be the mass of the car the force applied
since F = m *a
we get F = m * 6 => m = F/6.
now if a block of mass 'm'. Therefore mass the engine has to pull = 2m
since force applied by engine is constant F =
(2m)*A (A is the new acceleration)
now we put value of m (F/6) in this equation
and we get F = 2(F/6)*A
on solving A = 3 m/s².
.....
..
whatever be the mass of the car the force applied
since F = m *a
we get F = m * 6 => m = F/6.
now if a block of mass 'm'. Therefore mass the engine has to pull = 2m
since force applied by engine is constant F =
(2m)*A (A is the new acceleration)
now we put value of m (F/6) in this equation
and we get F = 2(F/6)*A
on solving A = 3 m/s².
Answered by
10
Answer:3
Step-by-step explanation:
let acceleration of car is a
F=ma
F=2ma'
a=2a'
a'=a/2
=6/2
=3m/s2
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