Question

The engine of a truck produces an acceleration of 2ms−2. If this truck draws another truck of the same mass, then the acceleration of the combination of trucks with the engine of truck 1 is

Answer 1

Answer:

whatever be the mass of the car the force applied

since F = m *a

we get F = m * 6 => m = F/6. 

now if a block of mass 'm'. Therefore mass the engine has to pull = 2m

since force applied by engine is constant F =

(2m)*A (A is the new acceleration) 

now we put value of m (F/6) in this equation

and we get F = 2(F/6)*A 

on solving A = 3 m/s².

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Explanation6:

Answer 2

Answer:

1 m/s^2

Explanation:

Mass= m, a= 2 m/s^2

F= ma

If mass(m) is doubled,

Then, acceleration= a/2 = 2/2 m/s^2 = 1 m/s^2