Question

the engines having different speed are to run on parallel tracks with starting point of the slower being ahead of the faster by 5km and 6km.in 2 separate cases. what is thr ratio between the distance and that the faster train has to travel in these cases to catchup with the slower
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Answer 1

Answer:

5:6

Explanation:

because the speed s are given 5km and 6km in two different casea

Answer 2

The Main Answer is:   5:6

Given: 2 trains, one faster and one slower

Distance between both trains is 5km and 6km in two different scenarios

Faster train is behind the slower train.

To Find: Ratio of distance that the faster train has to travel in order to surpass the slower train

Solution:

Given the distance between slower and faster trains is 5km and 6km in two separate cases.

Let the speed of the slower train is 'v kmph', and the speed of the faster train is 'v + x kmph'.

Using the concept of relative velocity, we assume the slower train to be stationary (v = 0)

This leaves only the faster train to be moving (with a speed of - 'x kmph').

Now, the distance for the faster train to cover in both cases is 5km and 6km respectively.

So, the ratio of distances to travel by the faster train is 5:6.

**Therefore required ratio of distances travelled by the faster train to surpass the slower train is

-- 5:6