Question

the enlarged image of an object placed at 60cm in front of a lens is obtained on a screen and distance of 120cm from it if the object is 5cm high then size of the image will be​

Answer 1

Answer:

Object distance u=−60 cmImage distance v=+120 cmUsing lens formula,1/f=1/v−1/u1/f=1/120−(−1/60)=+40cmH(image) / H(object) = v/uHi=−120/60X5=−10cm