Question

The enolic form of acetaldehyde contains –

(A) 6 Sigma bonds, 1 pi bond and 2 lone pairs

(B) 8 Sigma bonds, 2 pi bonds and 2 lone pairs

(C) 10 Sigma bonds, 1 pi bonds and 1 lone pair

(D) 9 Sigma bonds, 2 pi bond and 1 lone pair​

Answer 1

Answer:

(B) 8 Sigma bonds, 2 pi bonds and 2 lone pairs

Explanation:

this is answer

Answer 2

Answer:

Enols are a kind of reactive structure or intermediate in organic chemistry that is described as an alkene (olefin) with a hydroxyl group linked to one end of the alkene double bond.

Explanation:

The molecular formula and the chemical formula of acetaldehyde are C₂H₄O and CH₃CHO respectively.

The keto form of the acetaldehyde is HC-CH(=O) and the enol form of the acetaldehyde is H₂C=CH(OH).

Thus, in the enol form of acetaldehyde, there are 6 sigma bonds, 1 pi bond and 2 lone pairs.

Six sigma bonds are formed by four C-H bonds, one O-H bond, and one C-O bond.

The oxygen has two lone pairs of electrons.

There is one pi-bond present between the two carbon atoms.

Hence, the correct option is (A) 6 Sigma bonds, 1 pi bond, and 2 lone pairs.

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