Question

the enthalpies of formation of N2O and NO are 82 and 90 kg mol-1 respectively .the enthaphy of the reaction 2N2O+O2=4NO​

Answer 1

Answer:

196kJ

Explanation:

N2 + (1/2)O2 -------> N2O. ∆f = 82.........1

(1/2)N2 + (1/2)O2 ------> NO ∆f = 90....... 2

reverse 1 and multiply it by 2

multiply 2 by 4

and add then

2N2O -----> 2N2 + O2 .....∆f = (-82×2)

2N2 + 2O2 ------> 4NO ∆f = (90×4)

2N2O + O2 -------> 4NO

∆H = (90×4) + (-82×2)

∆H = 360 - 164 = 196kJ