The enthalpies of neutralisation for CH3COOH with NaOH and NH4OH with HCl are -50.6 and -51.4 kJ eq-1 respectively . Calculate the enthalpy of neutralisation of CH3COOH with NH4OH ?
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Answer: The enthalpy of neutralization will be -44.38 kJ/eq.
Explanation: We are given two neutralization reactions:
; ...(1)
; ...(2)
Equation 1 is the reaction of strong base and weak acid & equation 2 is the reaction of strong acid and weak base.
To form the equation in which reacts with , we write another equation, which will be subtracted from equation 1 and equation 2.
Equation for the reaction of strong acid and strong base:
; ...(3)
Subtracting equation 3 from 1 and 2, we get
...(4)
So, the calculations for enthalpies will be:
So, the enthalpy of neutralization of equation 4, will be -44.38 kJ/eq.
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