Question

The enthalpies of the following reactions are shown below.
[AFMC 2011]
1/2 H₂(g) + 1/2 O₂(g) → OH(g) ; ∆H = 42.09 kJ mol⁻¹
H₂(g) → 2H(g) ; ∆H = 435.89 kJ mol⁻¹
O₂(g) → 2O(g) ; ∆H = 495.05 kJ mol⁻¹
Calculate the O –– H bond energy for the hydroxyl radical.
(a) 223.18 kJ mol⁻¹ (b) 423.38 kJ mol⁻¹
(c) 513.28 kJ mol⁻¹ (d) 113.38 kJ mol⁻¹

Answer 1

$\huge\bold\red{Answer:-}$

(c) 513.28 kJ mol⁻¹

Answer 2

$\huge{\underline{\mathbb{\red{Answer}}}}$

(c) 513.28 kJ mol⁻¹

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