Question

The enthalpy change for reaction $\frac{1}{2} X_2(g) + \frac{3}{2} Y_2(g) \rightarrow XY_3(g)$ is – 50 kJ mol⁻¹. If the bond enthalpies of X–X and X–Y are respectively 380 and 150 kJ mol⁻¹ the bond enthalpy of Y–Y in kJ mol⁻¹ is
(a) 35
(b) 210
(c) 280
(d) 140

Answer 1

b). 280______

I hope this help