Question

The enthalpy change for the reaction :
2NH,g) -> N2(g) + 3H2(g)
is 92.2 kJ. What is the enthalpy of formation of ammonia?​

Answer 1

Answer:

.........?............?................

Answer 2

Explanation:

The enthalpy of formation of ammonia is −46.0 kJ mol −1 .

1/2 N2

+3/2 H 2

→NH 3

ΔH=−46.0kJ/mol

Multiply above equation with 2.N 2

+3H2

→2NH 3

ΔH=−46.0×2=−92.0kJ/mol

Reverse above equation

2NH 3

→N 2

+3H 2

ΔH=+92.0kJ/mol

The enthalpy change for the reaction 2NH3

→N 2

+3H 2

is 92.0 KJ mol −1

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