Question

the enthalpy change for the transition of the ice to liquid water 6.0 KJ mol at 273 k. calculate the entropy change for the process..??????​

Answer 1

Answer:

Enthalpy change (∆H) = 6.0 KJ mol

Temperature (T) = 273 k

Entropy change (∆S) = ???

We know that...

∆H = T∆S

∆S = ∆H/T

∆S = 6.0 / 273 KJ^-1 Mol

∆S = 0.022 kJ k^-1 mol.

Answer 2

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