Question

The enthalpy change of reaction 1 is -114 kJmol.

2NaOH(aq) + H2SO4(aq) →
Na2SO4(aq) + 2H2O(I) [reaction 1]

By using this information, what is the most likely value for the enthalpy change of reaction 2?

Ba(OH)2(aq) + 2HCl(aq) → BaCl2(aq) + 2H20(I) [reaction 2]


(EXPLAIN ME THIS WITH ANSWER PLEASE)​

Answer 1

Answer:

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Explanation:

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Answer 2

Answer:

enthalpy of reaction is - 114 kJmol-1

Explanation:

HCl is a monobasic acid. Thus, it is weaker than H2SO4. The enthalpy change of the reaction is negative, implying heat released to the surrounding. Hence, less heat will be released to the surrounding with HCl. BUT, reactivity (solubility of hydroxide)  increases down group 2. Hence, Ba(OH)2 is more reactive than NaOH. Thus, more heat is released to the surrounding. Both effects cancel each other and hence, the enthalpy change for both reaction is the same.