Chemistry, asked by kabirsingla7706, 11 months ago

The enthalpy changes for the following processes are listed below :
Cl_2(g) \rightarrow 2Cl(g), 242.3 kJ mol⁻¹
I_2(g) \rightarrow 2I(g), 151.0 kJ mol⁻¹
ICl(g) \rightarrow I(g) + Cl(g), 211.3 kJ mol⁻¹
I_2(s) \rightarrow I_2(g), 62.76 kJ mol⁻¹
Given that the standard states for iodine and chlorine are I₂(s) and Cl₂(g), the standard enthalpy of formation for ICl(g) is :
(a) +16.8 kJ mol⁻¹
(b) +244.8 kJ mol⁻¹
(c) –14.6 kJ mol⁻¹
(d) –16.8 kJ mol⁻¹

Answers

Answered by purvi200428
0

(a) part is the correct option


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