Chemistry, asked by manofredandgold3000, 4 months ago

The enthalpy changes of two reactions are shown.
AH = -34. OkJ mot
K2CO3(s) + 2HCl(aq) + 2Cl(aq) + H2O(l) + CO2(9)
KHCO3(s) + HCl(aq) → KCl(aq) + H2O(l) + CO2(g)
AH = +32.8 kJ mol
What is the enthalpy change for the reaction shown?
2KHCO3(s) → K2CO3(s) + H2O(l) + CO2(g)​

Answers

Answered by PranayLTorave
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Answer:

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