Question

The
enthalpy combustion of methane,
graphite and dehydrogen
at 298k are
- 890.3 kJ mol-1, -393.5 kJ mol-1 and -285.8 kJ mol-1.
kJ mol-1 resp. Enthalpy of f
ormation of
CH4 (g) will be​

Answer 1

Explanation:

The complete equation is

CH4 (g) + 2O2 (g) = CO2 (g) + 2H2O (l)

delta H combustion =

deltaH (formation of products) - deltaH (formation of reactants)

-890.3 = 2 (-285.8) + (-393.5) - delta H (formation of CH4)

delta H = - 74.8 KJ/mol