Question

the enthalpy of combustion of CH4 , graphite , dihydrogen are -890.3, -393.5 , -285.8KJ/mol. calculate∆f H° Ch4?????​

Answer 1

Answer:

∆f H° => -74.2 kJ/mol

Explanation:

C + 2 H2 => CH4

∆f H° = enthalpy of combustion of reactant - enthalpy of combustion of product

∆f H° => [-393.5 + 2(-285.5)] - (-890.3) kJ/mol

∆f H° => -74.2 kJ/mol.