Question

The enthalpy of combustion of methane, graphite and dihydrogen at 298 K are, - 890·3 kJ$mol^{-1}$, -393.5 kJ$mol^{-1}$ and –285.8 kJ$mol^{-1}$ respectively. Enthalpy of formation of $CH_{4}$ (g) will be: (i) - 74.8 kJ$mol^{-1}$ (ii) - 52.27 kJ$mol^{-1}$ (iii) + 74.8 kJ$mol^{-1}$ (iv) + 52.26 kJ$mol^{-1}$

Answer 1

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Answer 2

Answer:

Solution : (i) In case of liquid , viscosity increase with increase in density and for gases, it decreases with increase in density. (ii) with the rise in temperature, the viscosity of liquid decrease while that of gases increases. ... The viscosity of water decreases with the increase in pressure.Solution : (i) In case of liquid , viscosity increase with increase in density and for gases, it decreases with increase in density. (ii) with the rise in temperature, the viscosity of liquid decrease while that of gases increases. ... The viscosity of water decreases with the increase in pressure.The constant, further, is the same for all gases, provided that the mass of gas being compared is one mole, or one molecular weight in grams. For one mole, therefore, pV/T = R. The dimensions of the universal gas constant R are energy per degree per mole.Solution : (i) In case of liquid , viscosity increase with increase in density and for gases, it decreases with increase in density. (ii) with the rise in temperature, the viscosity of liquid decrease while that of gases increases. ... The viscosity of water decreases with the increase in pressure.The constant, further, is the same for all gases, provided that the mass of gas being compared is one mole, or one molecular weight in grams. For one mole, therefore, pV/T = R. The dimensions of the universal gas constant R are energy per degree per mole.Solution : (i) In case of liquid , viscosity increase with increase in density and for gases, it decreases with increase in density. (ii) with the rise in temperature, the viscosity of liquid decrease while that of gases increases. ... The viscosity of water decreases with the increase in pressure.The constant, further, is the same for all gases, provided that the mass of gas being compared is one mole, or one molecular weight in grams. For one mole, therefore, pV/T = R. The dimensions of the universal gas constant R are energy per degree per mole.Solution : (i) In case of liquid , viscosity increase with increase in density and for gases, it decreases with increase in density. (ii) with the rise in temperature, the viscosity of liquid decrease while that of gases increases. ... The viscosity of water decreases with the increase in pressure.The constant, further, is the same for all gases, provided that the mass of gas being compared is one mole, or one molecular weight in grams. For one mole, therefore, pV/T = R. The dimensions of the universal gas constant R are energy per degree per mole.Solution : (i) In case of liquid , viscosity increase with increase in density and for gases, it decreases with increase in density. (ii) with the rise in temperature, the viscosity of liquid decrease while that of gases increases. ... The viscosity of water decreases with the increase in pressure.The constant, further, is the same for all gases, provided that the mass of gas being compared is one mole, or one molecular weight in grams. For one mole, therefore, pV/T = R. The dimensions of the universal gas constant R are energy per degree per mole.The constant, further, is the same for all gases, provided that the mass of gas being compared is one mole, or one molecular weight in grams. For one mole, therefore, pV/T = R. The dimensions of the universal gas constant R are energy per degree per mole.The constant, further, is the same for all gases, provided that the mass of gas being compared is one mole, or one molecular weight in grams. For one mole, therefore, pV/T = R. The dimensions of the universal gas constant R are energy per degree per mole.The constant, further, is the same for all gases, provided that the mass of gas being compared is one mole, or one molecular weight in grams. For one mole, therefore, pV/T = R. The dimensions of the universal gas constant R are energy per degree per mole.The constant, further, is the same for all gases, provided that the mass of gas being compared is one mole, or one molecular weight in grams. For one mole, therefore, pV/T = R. The dimensions of the universal gas constant R are energy per degree per mole.