Question

The enthalpy of neutralisation of HCI and
NaOH is -57 kJ mol!. The heat evolved at
constant pressure (in kJ) when 0.5 mole of
H, SO
react with 0.75 mole of NaOH is equal
to
(1) 57 x 3/4
(2) 57 x 0.5
(3) 57
(4) 57 x 0.25​

Answer 1

Answer:

2

Explanation:

57×0.5

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