Question

The entire surface of a cone is
$22m {}^{2}$
. Its oblique height is 6 times its base. What will be the diameter of the base?​

Answer 1

Answer: use formula 2pie*r*h then find

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Step-by-step explanation:

Answer 2

Answer:

2 m

Step-by-step explanation:

Let

L= oblique height

R = radius of base

then total surface area of cone

A= area of base + curved area

=( pi)*R^2 + (pi)*R*L

given

L=6R

A= (pi)*R^2+(pi)*R*6R

A= (pi)*R^2 + 6*(pi)*R^2

A= 7*(pi)*R^2

Given A= 22 SQM

thus,

7*(pi)*R^2 = 22

R^2 = 22/7(pi)

R^2 = pi/pi

R^2 = 1

R= 1 (taking positive value only)

diameter = 2R = 2m