Chemistry, asked by anujranjan5866, 11 months ago

The entropy change involved in the isothermal reversible expansion of 2 moles of an ideal gas from a volume of 10 dm3 at 27°C is to a volume of 100 dm3
A) 42.3 J/ mole / K
B) 38.3 J/ mole / K
C) 35.8 J/ mole / K
D) 32.3 J/ mole / K

Answers

Answered by naza650
8

Answer:

B

Explanation:

∆S = 2.303 * 2 * 8.314 log 100÷10=

∆S = 38.3

Answered by hermanumrao
0

Answer:

Explanation:

entropy change of reaction is 38.3J/mol K

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