Question

The entropy of vaporization of a liquid is 60 J/k/mol and enthalpy of vaporization is 30 KJ/mol The boiling point of liquid is -

Answer 1

Solution is in the attachment:

Answer 2

Boiling point of liquid is 500 K

Explanation:

To calculate the temperature , we use the equation:

$\Delta S_v=\frac{\Delta H_{v}}{T}$    

where,  

$\Delta S_v$ = Entropy of vaporization  = 60 J/Kmol

$\Delta H_{v}$ = enthalpy of vaporization  = 30kJ/mol = 30000J/mol     (1kJ=1000J)

T = Boiling point = ?

$60J/Kmol=\frac{30000J}{T}$

$T=500K$

Thus boiling point of liquid is 500 K

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