Question

the eq x² - 8x + k =0 has real and distinct roots if...​

Answer 1

Answer:

compare ,

x² -8x + k=0 with ax² + bx + c = 0

a = 1, b = -8, c=k

it is given that roots are distinct and real,

discriminant ≥ 0

b²-4ac≥0

(-8)² - 4 x 1 x k ≥0

64-4k≥0

4k ≤ 64

k≤ 64/4

k≤16

I hope this helps you.

Answer 2

Step-by-step explanation:

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♡ ↪ The quadratic will have real root only when its discriminant will be greater than or equal to 0

Discriminant of given equation =b

2

−4ac =(−8)

2

−4×1×k>0

⇒64−4k>0

⇒4k<64

⇒k<16

So, the value of k should be less than 16.

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